2. The formula for a regression equation is Y’ = 2X + 9.
a. What would be the predicted score for a person scoring 6 on X?
The predicted score for that person would be,
Y = 2*6+9 = 21
b. If someone’s predicted score was 14, what was this person’s score on X?
In this case Y = 14 thus,
14 = 2X+9
 X = (149)/2 = 2.5
Thus the score on X was 2.5.
6. For the X, Y data below, compute:
a. r and determine if it is signiﬁcantly different from zero.
The obtained output from Minitab is given below,
Correlation: X, Y
Pearson correlation of X and Y = 0.849
PValue = 0.032
From the above output we can see that the correlation coefficient between X and Y is 0.849 with corresponding P value 0.032. As the P value is smaller than the significance level of 0.05 so we can conclude that the correlation coefficient is significantly different from zero.
b. the slope of the regression line and test if it differs signiﬁcantly from zero.
Using the data analysis tool pack of Excel the obtained output is given below,
SUMMARY OUTPUT 

Regression Statistics 

Multiple R 
0.8492 

R Square 
0.7211 

Adjusted R Square 
0.6514 

Standard Error 
3.5028 

Observations 
6 

ANOVA 


df 
SS 
MS 
F 
Significance F 

Regression 
1 
126.9207 
126.9207 
10.3441 
0.0324 

Residual 
4 
49.0793 
12.2698 

Total 
5 
176 





Coefficients 
Standard Error 
t Stat 
Pvalue 
Lower 95% 
Upper 95% 
Intercept 
3.1231 
3.1085 
1.0047 
0.3719 
5.5075 
11.7537 
X 
1.1332 
0.3523 
3.2162 
0.0324 
0.1550 
2.1115 
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