18. You choose an alpha level of .01 and then analyze your data.
a. What is the probability thxxxxxxxxxxxxxxxat you will make a Type I error given that the null hypothesis is true?
The probability of type I errorxxxxxxxxxxxxxxxxxxxxxxxxxxx is actually alpha given that the null hypothesis is true so it is 0.01.
b. What is the probability that you will make a Type I error given that the null hypothesis is false?
When null hypothesis is false, it is impossible to make a type I error. It means probability that you will make a type I error given that the null hypothesis is false is zero.
7. Below are data showing the results of six subjects on a memory test. The three scores per subject are their scores on three trials (a, b, and c) of a memory task. Are the subjects get- ting better each trial? Test txxxxxxxxxxxxxxhe linear effect of trial for the data.
a. Compute L for eachxxxxxxxxxxxxxxxxxxxxxx subject using the contrast weights -1, 0, and 1. That is, compute (-1)(a) + (0)(b) + (1)(c) for each subject.
b. Compute a one-sample t-test on this column (with the L values for each subject) you created.
M=Sample xxxxxxxxxxMean = (3+5+3+6+5+0)/6 = 3.667
Standard error xxxxxxxxxxxxxxoxxxxxxxxxf mean = Sm = 2.160/sqrt(6) = 0.8819
t=(M-mu)/Sm = 3.6x7/0.8819 = 4.158
Using calculator, wxxxxxxxxxxxxxxxxxe find out the probability of two tailed test to be 0.0088
13. You are conducting a study to see if students do better when they study all at once or in intervals. One groupxxxxxxxxxxxxxxxxxxxx of 12 participants took a test after studying for one hour continuously. The other group of 12 participants took a test after studying for three twenty minute sessions. The first group had a mean score of 75 and a variance of 120. The second group had a mean score of 86 and a variance of 100.